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3x^2-115x-186=0
a = 3; b = -115; c = -186;
Δ = b2-4ac
Δ = -1152-4·3·(-186)
Δ = 15457
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-115)-\sqrt{15457}}{2*3}=\frac{115-\sqrt{15457}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-115)+\sqrt{15457}}{2*3}=\frac{115+\sqrt{15457}}{6} $
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